[AT] Having battery problems--so how to fix?

[charlie hill]

Sometimes when I want to convert something from F to C I can't remember if 
it is 5/8 or 5/9.  When that happens I do this.  I know that boiling is 212 
F and 100 deg C (at sea level) and freezing is at 32 F and 0 C.    So if you 
subtract 32 from 212 you end up with 180 and the ratio becomes 100/180 or 
5/9.  To go the other  way it's just 9/5 and add the 32 back in.

By the way, what is it that has a 5/8 ratio?  Is it harmonics?   Can't 
remember.

Charlie
----- Original Message ----- 
From: "Larry D. Goss" <rlgoss at evansville.net>
To: "'Antique tractor email discussion group'" 
<at at lists.antique-tractor.com>
Sent: Saturday, April 01, 2006 8:02 AM
Subject: RE: [AT] Having battery problems--so how to fix?


> Don't feel bad about it, Henry.  We all get to the stage where we laugh
> at the same jokes every day because we can't remember that we ever heard
> them before.  I'm about to join that generation myself, but if you talk
> to my wife she'll tell you that I joined it about 40 years ago.  When it
> comes to temperature conversion, I just look at a thermometer and read
> whichever scale I want.  Likewise on metric measurement -- I just push
> the button on the vernier caliper that puts it in the units I want to
> work with.
>
> Larry
>
> -----Original Message-----
> From: at-bounces at lists.antique-tractor.com
> [mailto:at-bounces at lists.antique-tractor.com] On Behalf Of Henry Miller
> Sent: Friday, March 31, 2006 11:19 PM
> To: Antique tractor email discussion group
> Subject: Re: [AT] Having battery problems--so how to fix?
>
> On Friday 31 March 2006 22:34, Larry D. Goss wrote:
>> 20C = 68F.  That's been drilled into my head so much because of photo
>> processing that I'll never forget it.  Plugging those known numbers
> into
>> your "by guess and by gosh" equations gives:
>>
>> C/2 + 30 = F
>> 20/2 + 30 = F
>> 10 + 30 = F
>> 40 = F or 20C = 40F
>>
>> and
>>
>> (F-30) * 2 = C
>> (68-30) * 2 = C
>> 38 * 2 = C
>> 86 = C or 68F = 86C
>
> Looks like I mixed the conversion up.  Try the following corrected
> version:
> C*2+30 =f
> 20*2 + 30 = f
> 40 + 30 = f
> 20 C = 70 F.    Very close to 68.
>
> (f-30)/2 = c
> (68 - 30) / 2 = c
> 38 / 2 = c
> C = 16.  Not too far from the correct 20.
>
> I remember these by water freezes at 32 F, and 0C.   So you need to deal
> with
> that 30 degrees to normalize the starting point, and then properly
> divide/multiply by 2, remember that 2 degrees F is about 1 degree C.
> I can
> never remember the math formulas, but with the above knowledge I can
> figure
> it out in my head.
>
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