[AT] Having battery problems--so how to fix?

[Larry D. Goss]

Don't feel bad about it, Henry.  We all get to the stage where we laugh
at the same jokes every day because we can't remember that we ever heard
them before.  I'm about to join that generation myself, but if you talk
to my wife she'll tell you that I joined it about 40 years ago.  When it
comes to temperature conversion, I just look at a thermometer and read
whichever scale I want.  Likewise on metric measurement -- I just push
the button on the vernier caliper that puts it in the units I want to
work with.

Larry

-----Original Message-----
From: at-bounces at lists.antique-tractor.com
[mailto:at-bounces at lists.antique-tractor.com] On Behalf Of Henry Miller
Sent: Friday, March 31, 2006 11:19 PM
To: Antique tractor email discussion group
Subject: Re: [AT] Having battery problems--so how to fix?

On Friday 31 March 2006 22:34, Larry D. Goss wrote:
> 20C = 68F.  That's been drilled into my head so much because of photo
> processing that I'll never forget it.  Plugging those known numbers
into
> your "by guess and by gosh" equations gives:
>
> C/2 + 30 = F
> 20/2 + 30 = F
> 10 + 30 = F
> 40 = F or 20C = 40F
>
> and
>
> (F-30) * 2 = C
> (68-30) * 2 = C
> 38 * 2 = C
> 86 = C or 68F = 86C

Looks like I mixed the conversion up.  Try the following corrected
version:
C*2+30 =f
20*2 + 30 = f
40 + 30 = f
20 C = 70 F.    Very close to 68.

(f-30)/2 = c
(68 - 30) / 2 = c
38 / 2 = c
C = 16.  Not too far from the correct 20.

I remember these by water freezes at 32 F, and 0C.   So you need to deal
with 
that 30 degrees to normalize the starting point, and then properly 
divide/multiply by 2, remember that 2 degrees F is about 1 degree C.
I can 
never remember the math formulas, but with the above knowledge I can
figure 
it out in my head.   

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