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<p class="MsoNormal">Ohm’s Law<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal">Points open = no current flow = no voltage drop<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal">Points closed = current flow = voltage drop<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal"><b>From:</b> AT <at-bounces@lists.antique-tractor.com> <b>On Behalf Of
</b>Carl Szabelski<br>
<b>Sent:</b> Friday, August 27, 2021 10:53 AM<br>
<b>To:</b> Antique Tractor Email Discussion Group <at@lists.antique-tractor.com><br>
<b>Subject:</b> Re: [AT] tractor electrical question<o:p></o:p></p>
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<p class="MsoNormal" style="line-height:12.0pt;background:#FFC7CE"><b><span style="font-size:10.0pt;color:#9C0006">WARNING:</span></b><span style="font-size:10.0pt;color:black"> This message has originated from an External Source. This may be a phishing expedition
that can result in unauthorized access to our IT System. Please use proper judgment and caution when opening attachments, clicking links, or responding to this email.<o:p></o:p></span></p>
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<p class="MsoNormal">John,<o:p></o:p></p>
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<p class="MsoNormal">Found this article that might help explain the difference between ballasted and non-ballasted systems, and hopefully, help you with you issue. Still can’t see how the opening/closing of the points is affecting the voltage input to the coil
since there shouldn’t any affect on the primary side of the coil. Even if there was an internal short between the primary and secondary, that wouldn’t cause a 6V drop. Whatever is causing the voltage to drop has to be in-line with the coils + terminal. It
would have to somehow be tied into the primary side and untied as the points open/close.<o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">The points, condenser, rotor, spark plugs and coil secondary essentially form a separate circuit from the rest of the tractor’s electrical system, except of course, for the common ground. There are no external wires that tie into any other
circuit, and there should be no affect on the primary side to cause a voltage drop. Something on the primary side is apparently being tied in and out to cause the drop. Why it’s associated with the points is weird.<o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">Carl<o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal"><a href="https://nam02.safelinks.protection.outlook.com/?url=http%3A%2F%2Fclassicmini.weebly.com%2Fchoosing-a-coil.html&data=04%7C01%7C%7C5c7de4a2a4ef4d31d56e08d96972b789%7Ce3fefdbef7e9401ba51a355e01b05a89%7C0%7C0%7C637656765475242481%7CUnknown%7CTWFpbGZsb3d8eyJWIjoiMC4wLjAwMDAiLCJQIjoiV2luMzIiLCJBTiI6Ik1haWwiLCJXVCI6Mn0%3D%7C3000&sdata=U0yy4ITJLcK%2B5TkN3eBIeew5z2c6tGw5vlnNftHqXAE%3D&reserved=0">http://classicmini.weebly.com/choosing-a-coil.html</a>
<o:p></o:p></p>
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<p class="MsoNormal"><br>
<br>
On Thursday, August 26, 2021, Carl Szabelski <<a href="mailto:c.s.szabelski@gmail.com">c.s.szabelski@gmail.com</a>> wrote:<o:p></o:p></p>
<blockquote style="border:none;border-left:solid #CCCCCC 1.0pt;padding:0in 0in 0in 6.0pt;margin-left:4.8pt;margin-right:0in">
<p class="MsoNormal">If you’re reading 6V at the coil on a 12V system with the engine off and the ignition switch in the on position, then you’re dropping 6V from the starter relay to the coil. That would indicate you have a ballasted ignition system which
has a ballast resistor in the wire going from the relay to the coil. There should be a second wire attached to the + terminal of the coil that provides 12V during a start by temporarily bypassing the ballast resistor through the ignition switch when you start.
The reason the new coil is marked 6V is because that’s what you need. The coil should only need 6V when the engine is running. Running at 12V will cause the coil to overheat and eventually fail. Applying 12V during a start for a short time doesn’t hurt it.
<o:p></o:p></p>
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<p class="MsoNormal">If you don’t have the second wire, then you probably have a coil with an internal resistor. That requires 12V to the coil at all times, 6V will be dropped internally through the internal resistor. Maybe the PO did some rewiring and left
a ballast resistor in while putting in a coil with an internal resistor. If you do have an in-line ballast resistor and a coil with an internal resistor, then you have too much resistance and you’re dropping too much current going through the coil, which gives
you a weaker spark. That may be why putting 12V directly to the coil makes it run better. You’re overcoming the extra resistance with twice the voltage.<o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">The first thing you need to do is determine which type of system you have (ballasted or non-ballasted), and if you have the right coil (internal resistor or not). From looking at the wiring diagram I sent earlier it doesn’t seem to indicate
you should have a ballasted system since it doesn’t show a second wire at the coil. But again, maybe the PO made some modifications?<o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">Now if you’re dropping 6V at the starter relay, then the relay or the connection to the relay is suspect. That’s why I suggested testing the starter relay to see if you were dropping voltage there.<o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">Once you have a definite idea of what type of system you have, it should make finding the problem easier.<o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">Carl<o:p></o:p></p>
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<p class="MsoNormal"><br>
On Thursday, August 26, 2021, John Hall <<a href="mailto:jtchall@nc.rr.com" target="_blank">jtchall@nc.rr.com</a>> wrote:<o:p></o:p></p>
<blockquote style="border:none;border-left:solid #CCCCCC 1.0pt;padding:0in 0in 0in 6.0pt;margin-left:4.8pt;margin-right:0in">
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<p class="MsoNormal" style="margin-bottom:12.0pt">points, plugs, cap, rotor and coil are all new. I verified with my 50 year old parts book and it has the same part# for coil as what online parts at Case is showing. The new coil has 12V on the outside, but
the bill had 6V. Box was sealed up, but it came from overseas, so a lot of variables there<br>
<br>
Point gap was verified when I had the distributor off and plate out so I could make sure weights were free and springs not broken.<br>
<br>
I had my voltage regulator with me yesterday. When I tried to check at coil with engine running rough, it showed OL for whatever reason. I've checked so much stuff lately that I'm not sure but I think I got 6 and 12 volt readings depending on where the points
were once I shut the engine off. I tried checking the voltage with engine running at the fuel solenoid for reference and it was floating all over the place from 4 to 13.5V. This was observed with the engine hot and running rough. With engine not running it
holds steady a little over 12. <br>
<br>
Last night I also found that the wire to the coil and the wire to the R terminal on starter solenoid can read 6V (little less actually) while the wire going to the fuel solenoid in the carb was reading 12V.<br>
<br>
John Hall<br>
<br>
<br>
<o:p></o:p></p>
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<p class="MsoNormal">On 8/26/2021 6:35 PM, Howard Pletcher wrote:<o:p></o:p></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif">It's not unheard of, particularly since many of those parts now come from overseas. To me, swapping with another if you can find something to swap with would be the easiest way to prove or
eliminate that as a possibility. <o:p></o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif"><o:p> </o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif">Make sure your points setting is close to spec and they are clean as that would affect the ignition. Have you looked at your plugs, not thinking that's the problem, but if they are fouled or
badly gapped, they could have an effect. You also might run it until it heats up and needs the 12V to see if it still shows 6V to the coil. If not, then it's somewhere else in the circuit.<o:p></o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif"><o:p> </o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif">Many of the other things suggested have no connection with the ignition circuit. <o:p></o:p></span></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">On Thu, Aug 26, 2021 at 5:12 PM John Hall <<a href="mailto:jtchall@nc.rr.com" target="_blank">jtchall@nc.rr.com</a>> wrote:<o:p></o:p></p>
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<p class="MsoNormal" style="margin-bottom:12.0pt">Howard, you are leaning toward new coil and old coil are both bad?<br>
<br>
John Hall<o:p></o:p></p>
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<p class="MsoNormal">On 8/26/2021 3:47 PM, Howard Pletcher wrote:<o:p></o:p></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif">No, what he is reporting is just what should be happening. With the points open, no current is flowing through the primary circuit and there is 12V at the + side of the coil. When he bumped
the starter and closed the points, the current flowing through the resistor in the primary circuit results in a voltage drop so that there is now 6V on the coil as intended. <o:p></o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif"><o:p> </o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif">The wire from the starter to the coil does send 12V directly to the coil, but this is only engaged while the starter is cranking in order to produce a hotter spark for starting and is not connected
to 12V the rest of the time.<o:p></o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif"><o:p> </o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif">The fact the coil seems to require 12V to its terminal when hot points to an internal problem in the coil as discussed by Dell in the Yesterday's Tractors article.<o:p></o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif"><o:p> </o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif">Howard<o:p></o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif"><o:p> </o:p></span></p>
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<p class="MsoNormal"><span style="font-family:"Tahoma",sans-serif"><o:p> </o:p></span></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">On Thu, Aug 26, 2021 at 2:53 PM Carl Szabelski <<a href="mailto:c.s.szabelski@gmail.com" target="_blank">c.s.szabelski@gmail.com</a>> wrote:<o:p></o:p></p>
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<blockquote style="border:none;border-left:solid #CCCCCC 1.0pt;padding:0in 0in 0in 6.0pt;margin-left:4.8pt;margin-right:0in">
<p class="MsoNormal"> By the way, I believe it’s not the coil and is related to the cranking motor. Especially since the voltage drops when you bump it like you said. Something in the motor may be partially shorted or corroded, causing a voltage drop to the
coil. The coil should always see 12V whether or not there is a resistor, internal or external. The resistor is essentially after the coil winding and drops the voltage after the winding, not before it. If the engine is running fine when you directly connect
12V to the coil, the coil is working like it should and is good. <o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal" style="margin-bottom:12.0pt">Carl<br>
<br>
<o:p></o:p></p>
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<br>
<o:p></o:p></p>
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<o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">-- <o:p></o:p></p>
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<p class="MsoNormal">Howard<o:p></o:p></p>
</div>
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<p class="MsoNormal"><br>
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<pre>_______________________________________________<o:p></o:p></pre>
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