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There is a wire tied in from the starter solenoid also. You would
assume a new OEM coil to be good but who knows. All I know is it
acts the same with both coils. I will note that the new coil had to
be rotated 180 in the bracket to get it to hook up. The power is
going in the plus side, just like schematic shows. Maybe they just
put it in wrong at factory?<br>
<br>
John<br>
<br>
<div class="moz-cite-prefix">On 8/25/2021 11:52 PM, Jason wrote:<br>
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<div dir="auto">Generally most coils have a resistor before them
to lower the voltage so they don't burn up the points. Some
applications have a booster wire from the small terminal on the
starter solenoid. Since there is a voltage drop when cranking,
this booster wire temporarily raises the voltage to help during
starting.
<div dir="auto"><br>
</div>
<div dir="auto">If everything else is fine. A coil that fails as
it warms up is a coil getting close, to well, failing.</div>
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<div dir="auto">Jason</div>
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<br>
<div class="gmail_quote">
<div dir="ltr" class="gmail_attr">On Wed, Aug 25, 2021, 10:22 PM
Howard Pletcher <<a href="mailto:hrpletch@gmail.com"
moz-do-not-send="true">hrpletch@gmail.com</a>> wrote:<br>
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<div class="gmail_default"
style="font-family:tahoma,sans-serif">Is that the original
coil?</div>
<div class="gmail_default"
style="font-family:tahoma,sans-serif"><br>
</div>
<div class="gmail_default"
style="font-family:tahoma,sans-serif">I'm not familiar
with the 454, but in the truck world, most coils are
intended for 6V use. There is a resistor wire in the
harness that drops the voltage while the current is
flowing with the points closed. But there are also coils
intended for 12V use with no resistor wire. If that is
not the original coil, perhaps you have the wrong one.</div>
<div class="gmail_default"
style="font-family:tahoma,sans-serif"><br>
</div>
<div class="gmail_default"
style="font-family:tahoma,sans-serif">Since it seems to
work fine with 12V applied, I'd probably run another wire
from the ignition switch to the coil to bypass any
possible resistor wire.</div>
<div class="gmail_default"
style="font-family:tahoma,sans-serif"><br>
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<div class="gmail_default"
style="font-family:tahoma,sans-serif">Howard</div>
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<div class="gmail_quote">
<div dir="ltr" class="gmail_attr">On Wed, Aug 25, 2021 at
11:08 PM John Hall <<a href="mailto:jtchall@nc.rr.com"
target="_blank" rel="noreferrer" moz-do-not-send="true">jtchall@nc.rr.com</a>>
wrote:<br>
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<blockquote class="gmail_quote" style="margin:0px 0px 0px
0.8ex;border-left:1px solid
rgb(204,204,204);padding-left:1ex"><br>
If there is, I can't find it. Closes thing I have found is
the <br>
diode/rectifier for the alternator. Its inline and is tied
in on this <br>
particular "circuit" . Matter of fact, the side opposite
the alternator <br>
is where the fuel solenoid feeds from.<br>
<br>
John Hall<br>
<br>
<br>
On 8/25/2021 11:05 PM, Spencer Yost wrote:<br>
> Maybe there’s an external resistor?<br>
><br>
> Spencer<br>
><br>
> Sent from my iPhone<br>
><br>
>> On Aug 25, 2021, at 10:35 PM, John Hall <<a
href="mailto:jtchall@nc.rr.com" target="_blank"
rel="noreferrer" moz-do-not-send="true">jtchall@nc.rr.com</a>>
wrote:<br>
>><br>
>> Got what I hope is a simple question. On my IH
454 tractor, is the voltage going to the coil a constant
12V? I'm having some issues with it running bad when it
gets hot (I've already replaced everything but the plug
wires). Found out today that if I run a jumper wire from
battery to the coil, the problem goes away. Take it off
problem comes back, put it back it goes away, take it off,
it comes back. So I am tracing the wiring but this one
isn't simple, new enough there are tons of gauges, fuel
solenoids, safety switches, etc. Anyway, if I check
voltage at the coil, the fuel solenoid, and there is one
small terminal on starter solenoid that all read 12V if
the switch is on. If I bump the engine over slightly (I
guess the pts are closing) then the coil and starter drop
to just under 6V, fuel solenoid stays the same. So
shouldn't there always be 12V at the coil?<br>
>><br>
>> John Hall<br>
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<div dir="ltr">Howard</div>
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